题解 | #字符串字符匹配#
字符串字符匹配
https://www.nowcoder.com/practice/22fdeb9610ef426f9505e3ab60164c93
# !/usr/bin/env python3 # -*- coding: utf-8 -*- __author__ = 'tianyi' __date__ = '2024/3/23 20:04 ' __file__ = 'HW_HJ81.py' import sys # 1. 读取输入 need_match = "" n = 0 for i in sys.stdin: # 2. 按空格分割 n+=1 total = 0 if n%2 == 0: String1 = i.rstrip() for i in need_match: if i not in String1: print("false") break else: total += 1 if total == len(need_match): print("true") else: need_match = i.rstrip()
字符串可以遍历,可以使用 not in逻辑。