题解 | #n的阶乘#
n的阶乘
https://www.nowcoder.com/practice/97be22ee50b14cccad2787998ca628c8
#include <iostream>
#include <cstdio>
using namespace std;
long Function(int x){
if(x==1){
return x;
} else{
return x* Function(x-1);
}
}
int main() {
long n;
while (scanf("%ld",&n)!=EOF){
printf("%ld",Function(n));
}
return 0;
}
题目的数据范围更大，用long型，替代符事ld
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