题解 | #牛牛的短信#
牛牛的短信
https://www.nowcoder.com/practice/435c9e2bf4f84bee99b82ce84e95b0b7
#include <stdio.h>
float add(int arr[], int a);
int main()
{
//这里要用到数组,因为函数会销毁
int arr[100] = {0}, n = 0, i = 0;
float count = 0;
scanf("%d",&n);
for(i = 0;i < n; i++)
{
scanf("%d",&arr[i]);
}
count = add(arr,n);
printf("%.1f",count);
return 0;
}
float add(int arr[10], int a)
{
int i = 0;
float x = 0, sum = 0;
for(i = 0; i < a; i++)
{
if(arr[i] <= 60)
x = 0.1;
else
x = 0.2;
sum = sum + x;
}
return sum;
}
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