题解 | #从单向链表中删除指定值的节点#
从单向链表中删除指定值的节点
https://www.nowcoder.com/practice/f96cd47e812842269058d483a11ced4f
import sys
#实现目标，而结构可以忽略
s_list = [int(i) for i in input().split()]
m_list = []
m_list.append(s_list[1])
n = s_list[0]
for i in range(2,2*n-1,2):
# print(i)
a = s_list[i]#使用的数字
b = s_list[i+1]#前面的数字
# print(a,b)
m_list.insert(m_list.index(b)+1,a)
# print(m_list)
for i in range(2*n,len(s_list)):
m_list.remove(s_list[i])
print(*m_list)
