题解 | #牛牛学数列2#
牛牛学数列2
https://www.nowcoder.com/practice/fc72951f52984f3abd286d82eeffacba
#include <stdio.h> int main() { int n = 0; int i = 0; double sum = 0.0; scanf("%d", &n); for (i = 1; i <= n; i++) { double s = 1.0 / i; sum += s; } printf("%lf", sum); return 0; }