题解 | #求最小公倍数#

#include <iostream>
using namespace std;

int main() {
    int a, b;
    cin >> a >> b;

    if (a > b)
    {
        int tmp = b;
        b = a;
        a = tmp;        
    }

    int n;
    if (b % a == 0)
    {
        n = b;
    }
    else 
    {
        for (int i = 1;i <= b;i++)
        {
            int yueshu = i * a;
            if (yueshu % b == 0)
            {
                n = yueshu;
                break;
            }
        }
    }

    cout << n ;
}
// 64 位输出请用 printf("%lld")