题解 | #数字颠倒#

#include <iostream>
using namespace std;

int main() {
    int a;
    cin >> a;
    string res;
    if(a == 0){
        cout << "0" << endl;
    }
    while(a > 0){
        int b = a %10;
        a = a/10;
        res += ('0'+b);
    }

    cout << res << endl;

    return 0;
}
// 64 位输出请用 printf("%lld")