题解 | #获得积分最多的人(一)#
获得积分最多的人(一)
https://www.nowcoder.com/practice/1bfe3870034e4efeb4b4aa6711316c3b
SELECT
name,
SUM(grade_num) AS grade_num
FROM
(
SELECT
U.name AS name,
G.grade_num AS grade_num
FROM
grade_info AS G
LEFT JOIN user AS U ON U.id = G.user_id
) AS J
GROUP BY
name
ORDER BY
grade_num DESC
LIMIT
1;
查看23道真题和解析
