题解 | #平均活跃天数和月活人数#
平均活跃天数和月活人数
https://www.nowcoder.com/practice/9e2fb674b58b4f60ac765b7a37dde1b9
select date_format(submit_time,'%Y%m') as month, round(count(distinct uid,date_format(submit_time,'%Y%m%d'))/count(distinct uid),2) as avg_active_days, count(distinct uid) as mau from exam_record where start_time like'2021%' and submit_time is not null group by date_format(submit_time,'%Y%m');
最大的收获，原来count()函数里面可以有不止一列。。。
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