题解 | #国庆期间近7日日均取消订单量#
国庆期间近7日日均取消订单量
https://www.nowcoder.com/practice/2b330aa6cc994ec2a988704a078a0703
# 国庆头3天里,每天的近7日日均订单完成量和日均订单取消量,按日期升序排序。结果保留2位小数 # 日均订单完成量和日均订单取消量 近7日 国庆头3天里 # 订单完成:mileage is not null # 订单取消:mileage is nulll # 先计算每天的订单完成量和每天的订单取消量 # 再用窗口函数计算每天的近七日日均订单完成量和日均订单取消量 select * from( select date(co.order_time) as dt , round(avg(count(co.mileage)) over (order by date(co.order_time) range interval 6 day preceding), 2) as finish_num_7d , round(avg(count(case when co.mileage is null then 1 end)) over (order by date(co.order_time) range interval 6 day preceding), 2) as cancel_num_7d from tb_get_car_order as co group by date(co.order_time) ) as t where dt between '2021-10-01' and '2021-10-03' order by dt