题解 | #跳过列表的某个元素#
跳过列表的某个元素
https://www.nowcoder.com/practice/4713c1513cfa43b5a3dd0013059880fe
a = '1' for i in range(2,16): if i != 13: z=str(i) a="{} {}".format(a,z) else: continue print(a)
跳过列表的某个元素
https://www.nowcoder.com/practice/4713c1513cfa43b5a3dd0013059880fe
a = '1' for i in range(2,16): if i != 13: z=str(i) a="{} {}".format(a,z) else: continue print(a)
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