题解 | #链表内指定区间反转#
链表内指定区间反转
https://www.nowcoder.com/practice/b58434e200a648c589ca2063f1faf58c
/** * struct ListNode { * int val; * struct ListNode *next; * }; */ /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param head ListNode类 * @param m int整型 * @param n int整型 * @return ListNode类 */ struct ListNode* reverseBetween(struct ListNode* head, int m, int n ) { // write code here if (head == NULL || head->next == NULL || m == n) { return head; } struct ListNode* phead = head; struct ListNode* pend = head; struct ListNode* pphead = NULL; for (int i = 0; i < m - 1; i++) { pphead = phead; phead = phead -> next; } for (int i = 0; i < n - 1; i++) { pend = pend -> next; } struct ListNode* next = NULL; struct ListNode* prev = pend -> next; struct ListNode* curr = phead; pend -> next = NULL; while (curr != NULL) { next = curr -> next; curr -> next = prev; prev = curr; curr = next; } if(pphead != NULL){ pphead -> next = pend; }else{ head = pend; } return head; }