题解 | #删除字符串中出现次数最少的字符#

#include <iostream>
using namespace std;

int main() {
    string str;
    getline(cin, str);
    int a[26] = {0};
    int l = str.length();
    for (int i = 0; i < l; i++) {
        a[str[i] - 'a'] += 1;
    }
    int min = 21;
    for (int i = 0; i < 26; i++) {
        if ((a[i] <= min) && (a[i] != 0)) {
            min = a[i];
        }
    }
    for (int i = 0; i < l; i++) {
        if (a[(str[i] - 'a')] == min) {
            str.erase(i, 1);
            -- i;
        }
    }
    cout << str << endl;
}