题解 | #密码强度等级#

def fen(str1):
    i, j, k, m, l, g = 0, 0, 0, 0, 0, 0
    a, b = 0, 0
    c, d = 0, 0
    if len(str1) <= 4:
        l = 5
    elif 5 <= len(str1) <= 7:
        l = 10
    else:
        l = 25

    for i in str1:
        if 65 <= ord(i) <= 90:
            j = 10
        if 97 <= ord(i) <= 122:
            k = 10
        if 48 <= ord(i) <= 57:
            a = 10
            b += 1
        if int(0x21) <= ord(i) <= int(0x2F) or int(0x3A) <= ord(i) <= int(0x40):
            c = 10
            d += 1
        if int(0x5B) <= ord(i) <= int(0x60) or int(0x7B) <= ord(i) <= int(0x7E):
            c = 10
            d += 1
    if d > 1:
        c = 25
    if b > 1:
        a = 20

    if b > 0 and j + k == 10:
        m = 2
    if b > 0 and j + k == 10 and d > 0:
        m = 3
    if b > 0 and j + k == 20 and d > 0:
        m = 5

    return l + j + k + a + c + m


def pingfen(int1):
    if int1 >= 90:
        print("VERY_SECURE")
    elif int1 >= 80:
        print("SECURE")
    elif int1 >= 70:
        print("VERY_STRONG")
    elif int1 >= 60:
        print("STRONG")
    elif int1 >= 50:
        print("AVERAGE")
    elif int1 >= 25:
        print("WEAK")
    elif int1 >= 0:
        print("VERY_WEAK")


pingfen(fen(input()))

分阶段的把五种加分机制写出来，

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注意： int（）可以将字符串转换为整型，也可以将16进制转化为10进制。