题解 | #人民币转换#

s1,s2 = input().split('.')

string = '零壹贰叁肆伍陆柒捌玖拾'
#10000以内

def n2c(n):
    m = int(n)

    a = m//1000
    b = (m%1000)//100
    c = (m%100)//10
    d = m%10
    if a > 0:
        res.append(string[a]+'仟')
    elif a == 0 and n[0] == '0':
        res.append('零')
    if b > 0:
        res.append(string[b]+'佰')
    elif b == 0 and a != 0:
        res.append('零')
    if c > 0:
        if b == 0 and c == 1:
            res.append('拾')
        else:
            res.append(string[c]+'拾')

    elif c == 0 and b != 0:
        res.append('零')
    if d > 0:
        res.append(string[d])
res = ['人民币']
num1,num2 = int(s1),int(s2)
a = num1%10000
b = (num1//10000)%10000
c = num1//100000000
if c > 0:
    n2c(str(c))
    res.append('亿')

if b > 0:
    n2c(str(b))
    res.append('万')

if a > 0:
    n2c(str(a))
    res.append('元')

if num2 == 0:
    res.append('整')
else:
    if s2[0] == '0':
        res.append(string[num2]+'分')
    elif s2[1] == '0':
        res.append(string[num2//10]+'角')
    else:
        res.append(string[num2//10]+'角'+string[num2%10]+'分')
print(''.join(res))