题解 | #牛牛的矩阵相加#
牛牛的矩阵相加
https://www.nowcoder.com/practice/730b90507602412fac90a3f106bfa0cd
row1=[1,2,3]
row2=[4,5,6]
row3=[7,8,9]
n=int(input())
row1=list(map(lambda x:n*x,row1))
row2=list(map(lambda x:n*x,row2))
row3=list(map(lambda x:n*x,row3))
a=[]
a.extend([row1,row2,row3])
print(a)