题解 | #进制转换#

#include #include #include<math.h> using namespace std; int char2int(char a) { if(a-'0'>=0&&a-'0'<=9) { return a-'0'; } else { return a-'A'+10; } return 0; } int main(void) {

string s;
while(getline(cin, s))
{
    int sum=0;
    int len=s.length();
    int index=0;
    for(int i=len-1;i>=2;i--)
    {
       sum+= char2int(s[i])*pow(16,index);
        index++;
    }
    cout<<sum<<endl;
}
return 0;

}