//划分数组成两部分，和相等 //1 1 1 1 1  false; //1 2 3 4    true;  重点考虑 //首尾指针， 最后一种情况特殊考虑；    #include<bits/stdc++.h>  using namespace std; int main() {         int n;          cin >> n;         if(n == 1){             cout << "false" << endl;             return 0;         }                     vector<int> v;         int k;         for(int i = 0; i < n; ++i){             cin >> k;             v.push_back(k);         }                 sort(v.begin(), v.end());                                                                    int i = 0, j = n - 1;         int iPre = 0, jPre = n-1;         long long sum1 = v[0], sum2 = v[n-1];         while(i < j)         {             if(i != iPre)                 sum1 += v[i];             if(j != jPre)                 sum2 += v[j];                              if(sum1 == sum2){                 iPre = i;                 i++;                  jPre = j;                 j--;             }             else if(sum1 < sum2)             {                 iPre = i;                 i++;             }             else {                 jPre = j;                 j--;             }         }         if(sum1 == sum2 && i!=j )            cout << "true" << endl;         else if(sum1 > sum2){   //1 2 3 4 true;  重点考虑             k = 0;             while(sum1 > sum2) {                 sum1 -= v[k];                 sum2 += v[k];                 k++;             }              if(sum1 == sum2)                  cout << "true" << endl;             else                  cout << "false" << endl;         }         else                  cout << "false" << endl;                        return 0; }