题解 | 简单密码

# 思路:
# 1.用两个字典分别存储小写字母和大写字母的映射关系
# 2.遍历字符串,
# 2.1 如果是大写字母,去遍历dic_upper,使用replace()替换成对应的小写字母
# 2.2 如果是小写字母,去遍历dic_lower,使用replace()替换成对应的数字
# 3. 输出变换后的密码s

s = input() # 输入

dic_lower = {
    'a':'2','b':'2','c':'2','d':'3','e':'3','f':'3',
    'g':'4','h':'4','i':'4',
    'j':'5','k':'5','l':'5','m':'6','n':'6','o':'6',
    'p':'7','q':'7','r':'7','s':'7','t':'8','u':'8','v':'8',
    'w':'9','x':'9','y':'9','z':'9'} # 存放小写字母的映射关系

dic_upper = {
    'A':'b','B':'c','C':'d','D':'e','E':'f','F':'g','G':'h',
    'H':'i','I':'j','J':'k','K':'l','L':'m','M':'n','N':'o',
    'O':'p','P':'q','Q':'r','R':'s','S':'t','T':'u','U':'v',
    'V':'w','W':'x','X':'y','Y':'z','Z':'a'} # 存放大写字母的映射关系

# 遍历字符串
for i in s:
    if i in dic_lower.keys():
        s = s.replace(i, dic_lower[i])

for i in s:
    if i in dic_upper.keys():        # 注意:如果把两个if语句写在一个for循环下,大写字母就转换成数字了
        s = s.replace(i, dic_upper[i])

# 输出变换后的字符串(密码)
print(s)