题解 | 旋转数组
旋转数组
https://www.nowcoder.com/practice/e19927a8fd5d477794dac67096862042
import java.util.*;
public class Solution {
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
* 旋转数组
* @param n int整型 数组长度
* @param m int整型 右移距离
* @param a int整型一维数组 给定数组
* @return int整型一维数组
*/
public int[] solve (int n, int m, int[] a) {
m = m % n;
if (m == 0) {
return a;
}
//翻转第一部分
int k = Math.min(n - m, m);
for (int i = 0; i < k; i++) {
int temp = a[i];
int index = n - 1 - i;
a[i] = a[index];
a[index] = temp;
}
for (int i = k; i < n / 2; i++) {
int temp = a[i];
int index = n - 1 - i;
a[i] = a[index];
a[index] = temp;
}
for (int i = 0; i < m / 2; i++) {
int temp = a[i];
a[i] = a[m - 1 - i];
a[m - 1 - i] = temp;
}
for (int i = m; i < m + (n - m) / 2; i++) {
int temp = a[i];
a[i] = a[n - 1 - i + m];
a[n - 1 - i + m] = temp;
}
return a;
}
}
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