HJ41.称砝码 C语言 动态规划

称砝码

https://www.nowcoder.com/practice/f9a4c19050fc477e9e27eb75f3bfd49c

#include <stdio.h>
#include <stdbool.h>

int countWeights(int m[], int x[], int n) {
    int totalWeight = 0;
    for (int i = 0; i < n; i++) {
        totalWeight += m[i] * x[i];
    }
    bool dp[n + 1][totalWeight + 1];

    // 初始化,00为ture,其余元素为false
    for (int i = 0; i <= n; i++) {
        for (int j = 0; j <= totalWeight; j++) {
            dp[i][j] = false;
        }
    }
    dp[0][0] = true;

    for (int i = 1; i <= n; i++) {
        for (int j = 0; j <= totalWeight; j++) {
            dp[i][j] = dp[i - 1][j];
            for (int k = 1; k <= x[i - 1] && j - k * m[i - 1] >= 0; k++) {
                if (dp[i - 1][j - k * m[i - 1]]) {
                    dp[i][j] = true;
                    // printf("%d %d true\n", i, j);
                    break;
                }
            }
        }
    }

    int count = 1;  // 初始值设为1,包含重量0
    for (int j = 1; j <= totalWeight; j++) {
        if (dp[n][j]) {
            count++;
        }
    }

    return count;
}

int main() {
    int n;
    while (scanf("%d", &n) != EOF) {
        int m[n], x[n];
        for (int i = 0; i < n; i++) {
            scanf("%d", &m[i]);
        }
        for (int i = 0; i < n; i++) {
            scanf("%d", &x[i]);
        }
        int result = countWeights(m, x, n);
        printf("%d\n", result);
    }

    return 0;
}

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04-03 22:41
兰州大学 C++
老六f:有时候是HR发错了,我之前投的百度的后端开发,他给我发的算法工程师,但是确实面的就是百度开发
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