题解 | 牛客的课程订单分析(七)
牛客的课程订单分析(七)
https://www.nowcoder.com/practice/d6f4a37f966145da8900ba9edcc4c068
select (case
when b.name is null then 'GroupBuy' else b.name
end) as source,count(*) as cnt
from (select user_id,client_id,count(*) over(partition by user_id) as num
from order_info
where date > '2025-10-15' and status = 'completed' and product_name in ('C++','Java','Python')
) as a
left join client b on a.client_id = b.id
where a.num >= 2
group by name
order by source
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