题解 | 名字的漂亮度

T = int(input())
s_list = []
for i in range(T):
    s_list.append(input())

def count (c):    # 建立函数，将每一个字符串的字符频率写入字典
    count_dict = {}
    for i in c:
        if i in count_dict:
            count_dict[i] += 1
        else:
            count_dict[i] = 1
    return count_dict

for i in s_list:    # 循环所有字符串，用sorted()按照value大小从高到低排序，输出漂亮度
    num = 26
    sum = 0
    count_dict = count(i)
    new_count_dict = sorted(count_dict.items(), key = lambda x : x[1], reverse = True)
    for j, m in new_count_dict:
        sum += m * num
        num -= 1
    print(sum)