题解 | 牛牛的单链表求和

牛牛的单链表求和

https://www.nowcoder.com/practice/a674715b6b3845aca0d5009bc27380b5

#include <stdio.h>
#include <stdlib.h>
#define N 100


struct Node
{
    int data;
    struct Node *next;
};

struct Node* createList(int *arr,int n)
{
    struct Node*head = NULL, *tail = NULL;
    for(int i = 0; i < n; i++)
    {
        struct Node *newNode = (struct Node*)malloc(sizeof(struct Node));
        newNode -> data = arr[i];
        newNode -> next = NULL;
        if(head == NULL)
        {
            head = newNode;
            tail = newNode;
        }
        else {
        tail -> next = newNode;
        tail = newNode;
        }
    }
    return head;
}

int sumList(struct Node *head)
{
    int sum = 0;
    struct Node *p = head;
    while(p != NULL)
    {
        sum += p -> data;
        p = p -> next;
    }
    return sum;
}
int main()
{
    int n;
    scanf("%d",&n);
    int arr[N];
    int *p;
    for(int *p = arr; p < arr + n; p++)
    {
        scanf("%d",p);
    }

    struct Node *head = createList(arr,n);
    int total = sumList(head);
    printf("%d",total);

    return 0;
}

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