题解 | 回型矩阵
回型矩阵
https://www.nowcoder.com/practice/36d5dfddc22c4f5b88a5b2a9de7db343
#include <stdio.h>
int main()
{
int n = 0;
int k = 1;
scanf("%d", &n);
int a[20][20];
int up = 0, right = n - 1, down = n - 1, left = 0;
while (k <= n * n)
{
for (int i = up; i <= right; i++)
{
a[up][i] = k++;
}
up++;
for (int i = up; i <= down; i++)
{
a[i][down] = k++;
}
right--;
for (int i = right; i >= left; i--)
{
a[down][i] = k++;
}
down--;
for (int i = down; i >= up; i--)
{
a[i][left] = k++;
}
left++;
}
for (int i = 0; i < n; i++)
{
for (int j = 0; j < n; j++)
{
printf("%d", a[i][j]);
printf(" ");
}
printf("\n");
}
return 0;
}