题解 | 牛牛学数列
牛牛学数列
https://www.nowcoder.com/practice/0b97367cd2184c12a0e02f7c223aee11
#include <stdio.h>
int main() {
int n;
scanf("%d",&n);
int num = 0;//初始化为零
int sum = 0;
for(int i=1;i<=n;i+=2)//将偶数和奇数分出来了，奇数个赋予正数
{
num += i;
}
for(int i=2;i<=n;i+=2)//偶数赋予负数
{
sum += -1*i;
}
printf("%d",num + sum);//两者相加即可
return 0;
}
