题解 | 牛牛学数列
牛牛学数列
https://www.nowcoder.com/practice/0b97367cd2184c12a0e02f7c223aee11
#include <stdio.h>
int main() {
int n,s=0,c=1;scanf("%d",&n);
for(int i=1;i<=n;i++){
s=s+i*c;
c=-c;
}printf("%d",s);
return 0;
}
