题解 | KiKi和酸奶
KiKi和酸奶
https://www.nowcoder.com/practice/c7721f3a1b1a47a783974453e82cadbb
#include <stdio.h>
int main() {
int n,h,m;
scanf("%d %d %d",&n,&h,&m);
int left;
if ((m%h == 0 )) {//整数直接减去
left = n-(m/h) ;
}
else {//喝光一盒酸奶之前不会喝另一个==有余数且开了新的酸奶需要再减去一个
left = n-(m/h) -1;
}
printf("%d\n",left);
return 0;
}
