题解 | 牛牛的计划

#include <stdio.h>

int main() {
    int y, m, d;
    scanf("%d %d %d", &y, &m, &d);
    int y1, m1, d1;
    scanf("%d %d %d", &y1, &m1, &d1);

    if(y1>=y){//2022
        if(m1>=m){//1
            if(d1>=d){
                printf("yes");
            }
             else
                printf("yes");
        }
        else  printf("yes");
       
    }
     else
            printf("no");
    
    return 0;
}