题解 | 牛牛学数列
牛牛学数列
https://www.nowcoder.com/practice/0b97367cd2184c12a0e02f7c223aee11
#include <stdio.h>
int main()
{
int n = 0;
int count1 = 0;
scanf("%d", &n);
for (int i = 0; i <= n; i++)
{
if (i % 2 == 0)
{
count1 -= i;
}
else
{
count1 += i;
}
}
printf("%d\n", count1);
return 0;
}
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