题解 | 输出单向链表中倒数第k个结点
输出单向链表中倒数第k个结点
https://www.nowcoder.com/practice/54404a78aec1435a81150f15f899417d
while True: try: n, val, k = int(input()), input().split(), int(input()) print(val[n - k] if k else 0) except: break
输出单向链表中倒数第k个结点
https://www.nowcoder.com/practice/54404a78aec1435a81150f15f899417d
while True: try: n, val, k = int(input()), input().split(), int(input()) print(val[n - k] if k else 0) except: break
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