题解 | #字符统计# 字典多重排序
字符统计
https://www.nowcoder.com/practice/c1f9561de1e240099bdb904765da9ad0
s=input()
s1=set(s)
#print(s1)
res={}
for i in s1:
n=s.count(i)
res[i]=n
res1=sorted(res.items(),key=lambda x:(x[1],-ord(x[0])),reverse=True)
#print(res1)
print(''.join([i[0] for i in res1]))
字典多重排序：res1=sorted(res.items(),key=lambda x:(x[1],-ord(x[0])),reverse=True) 输出结果为列表
