题解 | #在字符串中找出连续最长的数字串#

import java.util.*;

// 注意类名必须为 Main, 不要有任何 package xxx 信息
public class Main {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        // 注意 hasNext 和 hasNextLine 的区别
        while (in.hasNextLine()) { // 注意 while 处理多个 case
            String s = in.nextLine();
            //存储结果-开头指针
            List<Integer> list = new ArrayList<>();
            char[] arr = s.toCharArray();
            int i = 0;
            int j = 0;
            int max = 0;
            while(j < arr.length){
                if(Character.isDigit(arr[j])){
                    if(!Character.isDigit(arr[i])){
                        i = j;
                    }
                    while(j < arr.length && Character.isDigit(arr[j])){
                        j++;
                    }

                    if(max < j-i){
                        list.clear();
                        list.add(i);
                        max  = j - i;
                    }else if(max == j - i){
                        list.add(i);
                    }
                    i = j;

                }else{
                    j++;
                }
            }

            for(int index : list){
                System.out.print(s.substring(index, index + max));
            }
            System.out.print("," + max);
            System.out.println();
        }
    }
}