题解 | #查询连续入住多晚的客户信息？#

select
    c.user_id as user_id,
    c.room_id as room_id,
    g.room_type as room_type,
    day(c.checkout_time) - day(c.checkin_time) as days
from
    guestroom_tb g,
    checkin_tb c
where
    g.room_id = c.room_id
    and day(c.checkout_time) - day(c.checkin_time) > 1
order by days asc ,c.room_id asc ,c.user_id desc