题解 | #坐标移动#

#-*- coding:utf-8 -*-
#自己实现的代码，逻辑应该是清晰的，但是比较繁琐
# string = list(input().strip().split(';'))
# i,j = 0,0
# #合法字符串
# move_str = ['A','D','W','S']
# digit = [str(i) for i in range(100)]
# leg_list = []
# for m in move_str:
#     for dig in digit:
#         leg_list.append(m + dig)
# for s in string:
#     if s not in leg_list: #非法字符直接跳过
#         continue
#     else: #对合法字符进行判断并移动
#         if s[0] == 'A':
#             i -= int(s[1:])
#         if s[0] == 'S':
#             j -= int(s[1:])
#         if s[0] == 'W':
#             j += int(s[1:])
#         if s[0] == 'D':
#             i += int(s[1:])
# print(str(i) + ',' + str(j))


#整合优秀题解代码——简短代码
string = list(input().strip().split(';'))
dic = {'A':0,'S':0,'W':0,'D':0}
for s in string:
    try: #利用try...except...进行判断分析
        pos = int(s[1:])
        dic[s[0]] += pos
    except:
        continue

print(str(dic['D'] - dic['A']) + ',' + str(dic['W'] - dic['S'])) #一步到位进行坐标计算