题解 | #在字符串中找出连续最长的数字串#

import java.util.*;

import java.io.*;
public class Main {
    public static void main(String[] args) throws IOException {
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        String str = null;
        StringBuilder sb = new StringBuilder();
        while ((str = br.readLine()) != null) {
            char[] chars = str.toCharArray();
            int[] dp = new
            int[chars.length]; //dp[i]：以i为尾的最长子串长度，dp[i] = Character.isDigit(chars[i]) ? dp[i - 1] + 1 : 0;
            dp[0] = Character.isDigit(chars[0]) ? 1 : 0;
            //计算最大值
            int max=dp[0];
            for (int i = 1; i < chars.length; i++) {
                dp[i] = Character.isDigit(chars[i]) ? dp[i - 1] + 1 : 0;
                max=Math.max(max,dp[i]);
            }
            //拼接所有最大值的字符串
            for (int i = 0; i < dp.length; i++) {
                if(dp[i]==max){
                    sb.append(str.substring(i - max + 1, i + 1));
                }
            }
            sb.append(",");
            sb.append(max);
            sb.append("\n");
        }
        System.out.print(sb.toString());
    }
}