题解 | #识别有效的IP地址和掩码并进行分类统计#
识别有效的IP地址和掩码并进行分类统计
https://www.nowcoder.com/practice/de538edd6f7e4bc3a5689723a7435682
import java.util.*;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int aNum = 0;
int bNum = 0;
int cNum = 0;
int dNum = 0;
int eNum = 0;
int errNum = 0;
int pNum = 0;
while (sc.hasNextLine()) {
String str = sc.nextLine();
String[] strArr = str.split("~");
int ipFirst = getIpSeg(strArr[0], 0);
if (ipFirst == 0 || ipFirst == 127) {
continue;
}
if (maskIsInvaild(strArr[1])) {
errNum++;
continue;
}
if (ipIsInvaild(strArr[0])) {
errNum++;
continue;
}
if (ipFirst >= 1 && ipFirst <= 126) {
aNum++;
}
if (ipFirst >= 128 && ipFirst <= 191) {
bNum++;
}
if (ipFirst >= 192 && ipFirst <= 223) {
cNum++;
}
if (ipFirst >= 224 && ipFirst <= 239) {
dNum++;
}
if (ipFirst >= 240 && ipFirst <= 255) {
eNum++;
}
int ipSecond = getIpSeg(strArr[0], 1);
if (ipFirst == 10 || (ipFirst == 172 && ipSecond >= 16 && ipSecond <=31) || (ipFirst == 192 && ipSecond == 168)) {
pNum++;
}
}
System.out.println(aNum + " " + bNum + " " + cNum + " " + dNum + " " + eNum + " " + errNum + " " + pNum);
}
public static boolean maskIsInvaild(String mask) {
String[] maskArr = mask.split("\\.");
if (maskArr.length != 4) {
return true;
}
String maskBinary = toBinary(maskArr[0]) + toBinary(maskArr[1]) + toBinary(maskArr[2]) + toBinary(maskArr[3]);
if (!maskBinary.matches("[1]{1,}[0]{1,}")) {
return true;
}
return false;
}
public static String toBinary(String num) {
String numBinary = Integer.toBinaryString(Integer.valueOf(num));
while (numBinary.length() < 8) {
numBinary = "0" + numBinary;
}
return numBinary;
}
public static boolean ipIsInvaild(String ip) {
String[] ipArr = ip.split("\\.");
if (ipArr.length != 4) {
return true;
}
if (Integer.valueOf(ipArr[0]) > 255 || Integer.valueOf(ipArr[1]) > 255 || Integer.valueOf(ipArr[2]) > 255 || Integer.valueOf(ipArr[3]) > 255) {
return true;
}
return false;
}
public static int getIpSeg(String ip, int index) {
String[] ipArr = ip.split("\\.");
return Integer.valueOf(ipArr[index]);
}
}
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