题解 | #记负均正#

#include <stdio.h>

int main() {
    int n,z=0,y=0;
    scanf("%d",&n);

    int num[n];
    for (int i = 0; i<n; i++) {
        scanf("%d",&num[i]);
        if (num[i] == 0) {
        y++;
        }
        if (num[i] < 0) {
            num[i] = 0;
        z++;
        }
    }

    float k=0.0;
    for (int i = 0; i<n; i++) {
        k += num[i];
    }
    if (k != 0) {
    printf("%d %0.1f",z,k/(n-z-y));//%0.1f结果保留一位小数
    }
    else {
    printf("%d 0.0",z);
    }
    

    return 0;
}