Python题解 | #输出单向链表中倒数第k个结点#
输出单向链表中倒数第k个结点
https://www.nowcoder.com/practice/54404a78aec1435a81150f15f899417d
while True: try: n = int(input()) list1 = list(map(int, input().strip().split(' '))) k = int(input()) if k == 0: print(0) else: print(list1[n - k]) except: break