题解 | #计算日期到天数转换#
计算日期到天数转换
https://www.nowcoder.com/practice/769d45d455fe40b385ba32f97e7bcded
#include <stdio.h> int main() { int year, month, day; while (scanf("%d %d %d", &year, &month, &day) != EOF) { //存储每个月的天数 int month_day[13] = {0,31,28,31,30,31,30,31,31,30,31,30,31}; //判断闰年 if(year % 4 == 0 && year % 100 != 0 || year % 400 == 0) month_day[2] = 29; //加天数 int days = 0; for(int i = 1; i < month; ++i) days += month_day[i]; days += day; printf("%d",days); } return 0; }