题解 | #打印日期#超级简单

#include <iostream>

using namespace std;

int daytab[2][13] = {
	{0,31,28,31,30,31,30,31,31,30,31,30,31},
	{0,31,29,31,30,31,30,31,31,30,31,30,31}
}; 

bool isLeapYear(int x){
	return (x % 4 == 0 && x % 100 != 0) || (x % 400 == 0);
}

int main(){
	int y,d;
	
	while(cin >> y >> d){
		int m = 0,flag = 0;
		if(isLeapYear(y)){
			for(int i = 0;i < 12; i ++){
				flag = d - daytab[1][i + 1];
				m ++;
				if(flag <= 0)break;
				else d = d - daytab[1][i + 1] ;
			}
		}else{
			for(int i = 0;i < 12; i ++){
				flag = d - daytab[0][i + 1];
				m ++;
				if(flag <= 0)break;
				else d = d - daytab[0][i + 1] ;
			}
		}
		printf("%04d-%02d-%02d\n",y,m,d);
	
		
	}
	return 0;
}