题解 | #二分查找-I#
二分查找-I
https://www.nowcoder.com/practice/d3df40bd23594118b57554129cadf47b
#include <vector> class Solution { public: int binarySearch(vector<int>& nums, int target, int start, int end) { if (end < start) { return -1; } int mid = (start + end)/2; if (nums[mid] < target) { start = mid + 1; return binarySearch(nums, target, start, end); } else if(nums[mid] > target){ end = mid - 1; return binarySearch(nums, target, start, end); } else { return mid; } } /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param nums int整型vector * @param target int整型 * @return int整型 */ int search(vector<int>& nums, int target) { // write code here return binarySearch(nums, target, 0, nums.size()-1); } };
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C++在线编程练习题解