题解 | #合并两个排序的链表#

# class ListNode:

# from numpy import result_type
#     def __init__(self, x):
#         self.val = x
#         self.next = None
#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param pHead1 ListNode类 
# @param pHead2 ListNode类 
# @return ListNode类
#
class Solution:
    def Merge(self , pHead1: ListNode, pHead2: ListNode) -> ListNode:
        # write code here
        list_num = []
        while pHead1:
            list_num.append(pHead1.val)
            pHead1=pHead1.next
        while pHead2:
            list_num.append(pHead2.val)
            pHead2=pHead2.next
        list_num.sort()
        dummy = ListNode(-1)
        cur =dummy
        print("list_num :",list_num)
        for i in range(len(list_num)):
            cur.next = ListNode(list_num[i])
            cur = cur.next
        return dummy.next

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