题解 | #KiKi和酸奶#
KiKi和酸奶
https://www.nowcoder.com/practice/c7721f3a1b1a47a783974453e82cadbb
#include <stdio.h>
int main() {
int n,m,h,reduce,result,add;
scanf("%d %d %d",&n,&h,&m);
add = 0;
if((m*1.0/h)>m/h)
{
add = 1;
}
reduce = m*1.0/h + add;
result = n - reduce;
printf("%d",result);
return 0;
}
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