题解 | #字符逆序#

#include <stdio.h>
#include <string.h>

#define N 10010

char s[N];

void reverse(char* s)
{
    int n = strlen(s);
    for (int i = 0; i < n / 2; i ++ )
    {
        char c = s[i];
        s[i] = s[n - i - 1];
        s[n - i - 1] = c;
    }
}

int main()
{
    scanf("%[^\n]", s);

    reverse(s);

    for (int i = 0; i < strlen(s); i ++ ) printf("%c", s[i]);
    
    return 0;
}