题解 | #有效括号序列#
有效括号序列
https://www.nowcoder.com/practice/37548e94a270412c8b9fb85643c8ccc2
class Solution {
public:
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param s string字符串
* @return bool布尔型
*/
bool isValid(string s) {
// write code here
if (s.size() <= 1)
return false;
stack<char> op;
char c;
int f = 0;
for (int i = 0; i < s.size(); i++) {
c = s[i];
if (c == '(' || c == '[' || c == '{')
op.push(c);
else if (c == ')' || c == '}' || c == ']') {
if (op.empty()) {
f = 1;
break;
} else {
if ((c == ')' && op.top() == '(')
|| (c == ']' && op.top() == '[')
|| (c == '}' && op.top() == '{'))
op.pop();
else {
f = 1;
op.push(c);
}
}
}
}
if (op.empty() && f == 0)
return true;
else
return false;;
}
};
