题解 | #遍历链表#

遍历链表

https://www.nowcoder.com/practice/7d348aa8b7d24e01a4f10bd023e2fb54

#include <stdio.h>

typedef struct Node {
    int value;
    struct Node* next;
} Node;

//按升序插入
void insert(Node* head, int newValue) {
    Node* newNode, *p, *pre;
    //创建新节点
    newNode = (Node*)malloc(sizeof(Node));
    newNode->value = newValue;
    newNode->next = NULL;
    //头插法
    if (head->next==NULL) {
        head->next = newNode;
    } else {
        pre = head;
        p = head->next;
        while (p != NULL && newValue > p->value) {
            pre = pre->next;
            p = p->next;
        }
        newNode->next = p;
        pre->next = newNode;
    }
}


int main() {
    int n;
    while (scanf("%d ", &n) != EOF) { // 注意 while 处理多个 case
        //带头节点
        Node* head = (Node*)malloc(sizeof(Node)),*p;
        head->value = 0;
        head->next = NULL;
        int newValue;
        for (int i = 0; i < n; i++) {
            scanf("%d ", &newValue);
            insert(head, newValue);
        }
	  //输出链表节点元素
        p = head->next;
        while (p != NULL) {
            printf("%d ", p->value);
            p = p->next;
        }
        printf("\n");
    }
    return 0;
}

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