题解 | #鸡兔同笼#
鸡兔同笼
https://www.nowcoder.com/practice/fda725b4d9a14010bb145272cababef1
#include <iostream>
#include <cstdio>
using namespace std;
int main() {
int a;
while (scanf("%d", &a) != EOF) {
int minimum = 0;
int maximum = 0;
if (a % 2 == 0) {
minimum = a / 4 + (a%4)/2;
maximum = a / 2;
}
cout << minimum << " " << maximum << endl;
}
return 0;
}
