题解 | #鸡兔同笼#

鸡兔同笼

https://www.nowcoder.com/practice/fda725b4d9a14010bb145272cababef1

#include <iostream>
#include <cstdio>

using namespace std;

int main() {
    int a;
    while (scanf("%d", &a) != EOF) {
        int minimum = 0;
        int maximum = 0;
        if (a % 2 == 0) {
            minimum = a / 4 + (a%4)/2;
            maximum = a / 2;
        }
        cout << minimum << " " << maximum << endl;
    }
    return 0;
}
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