题解 | #对称平方数1#

//前面学的逆序数刚好用上
#include<stdio.h>
using namespace std;

int Reverse( int n){
    int reverse = 0,remain;
    while(1){
        remain = n%10;
        reverse = reverse*10 + remain;
        n = n/10;
        if(0 == n){
            break;
        }
    }
    return reverse;
}

int main(){
    int n,square,N;
    
    for(n = 0;n<=256;++n ){
       square = n*n;
       N = Reverse(square);
       if(N == square){
        printf("%d\n",n);
       } 
    }
    return 0;
}