题解 | #链表内指定区间反转#
链表内指定区间反转
https://www.nowcoder.com/practice/b58434e200a648c589ca2063f1faf58c
class ListNode:
def __init__(self, x):
self.val = x
self.next = None
#
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
#
# @param head ListNode类
# @param m int整型
# @param n int整型
# @return ListNode类
#
class Solution:
def reverseBetween(self, head: ListNode, m: int, n: int) -> ListNode:
if not head:
return None
# 创建一个虚拟节点 dummy,作为链表的起始点
dummy = ListNode(0)
dummy.next = head
# 初始化指针
pre = dummy
for _ in range(m - 1):
pre = pre.next
# 反转链表
cur = pre.next
for _ in range(n - m):
temp = cur.next
cur.next = temp.next
temp.next = pre.next
pre.next = temp
return dummy.next
查看1道真题和解析